关于安捷伦datasheet中一处输出阻抗匹配的疑惑～

                    Figure23

这是MGA83563的2.5GHz输出阻抗匹配的　匹配过程及实现，是datasheet中提供的～但不包括红色部分，红色部分是自己画上去的。原文如下：
　Avago’s Touchstone program was used to interpolate the s-parameter data and calculate a Γml of 0.14 ∠172° for 2.5 GHz.
   This Γml point is plotted on the Smith chart in Figure 23 as
Point C, along with an indication of the area of lower impedance
from this point. (The output impedance is expected to
decrease under large signal conditions.) A two-element matching network consisting of a shunt capacitor and series transmission line is chosen to match the output to 50 ohms.
    Referring to the Smith chart in Figure 23, the initial output match
for Γml was determined to be a 0.4 pF shunt capacitor followed by a 0.32-inch length of 50 Ω microstripline.

首先，把我的疑惑说一下：
ａ，我认为Ｂ点应该在图中的Ｂ＇点。（至少匹配时要与r=1圆相交）
ｂ，既然要做并联电容匹配，就应该做导纳变换即Ｃ换到Ｃ＇
ｃ，而且对微带和容抗的计算结果也有出入，
其次，如果图中是按导纳圆匹配的，也有问题，既然是将输出阻抗匹配到传输线，确定微带线长时，怎么逆时针旋转反射系数到Ｂ点呢？应该是顺时针转到Ｂ＇的、对应的导纳点阿。

以上是我对这个数据手册的不解，请网站朋友的帮助。